Integrand size = 33, antiderivative size = 125 \[ \int \frac {(c-i c \tan (e+f x))^{5/2}}{a+i a \tan (e+f x)} \, dx=-\frac {3 i \sqrt {2} c^{5/2} \text {arctanh}\left (\frac {\sqrt {c-i c \tan (e+f x)}}{\sqrt {2} \sqrt {c}}\right )}{a f}+\frac {3 i c^2 \sqrt {c-i c \tan (e+f x)}}{a f}+\frac {i c^2 (c-i c \tan (e+f x))^{3/2}}{a f (c+i c \tan (e+f x))} \]
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Time = 0.22 (sec) , antiderivative size = 125, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {3603, 3568, 43, 52, 65, 212} \[ \int \frac {(c-i c \tan (e+f x))^{5/2}}{a+i a \tan (e+f x)} \, dx=-\frac {3 i \sqrt {2} c^{5/2} \text {arctanh}\left (\frac {\sqrt {c-i c \tan (e+f x)}}{\sqrt {2} \sqrt {c}}\right )}{a f}+\frac {3 i c^2 \sqrt {c-i c \tan (e+f x)}}{a f}+\frac {i c^2 (c-i c \tan (e+f x))^{3/2}}{a f (c+i c \tan (e+f x))} \]
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Rule 43
Rule 52
Rule 65
Rule 212
Rule 3568
Rule 3603
Rubi steps \begin{align*} \text {integral}& = \frac {\int \cos ^2(e+f x) (c-i c \tan (e+f x))^{7/2} \, dx}{a c} \\ & = \frac {\left (i c^2\right ) \text {Subst}\left (\int \frac {(c+x)^{3/2}}{(c-x)^2} \, dx,x,-i c \tan (e+f x)\right )}{a f} \\ & = \frac {i c^2 (c-i c \tan (e+f x))^{3/2}}{a f (c+i c \tan (e+f x))}-\frac {\left (3 i c^2\right ) \text {Subst}\left (\int \frac {\sqrt {c+x}}{c-x} \, dx,x,-i c \tan (e+f x)\right )}{2 a f} \\ & = \frac {3 i c^2 \sqrt {c-i c \tan (e+f x)}}{a f}+\frac {i c^2 (c-i c \tan (e+f x))^{3/2}}{a f (c+i c \tan (e+f x))}-\frac {\left (3 i c^3\right ) \text {Subst}\left (\int \frac {1}{(c-x) \sqrt {c+x}} \, dx,x,-i c \tan (e+f x)\right )}{a f} \\ & = \frac {3 i c^2 \sqrt {c-i c \tan (e+f x)}}{a f}+\frac {i c^2 (c-i c \tan (e+f x))^{3/2}}{a f (c+i c \tan (e+f x))}-\frac {\left (6 i c^3\right ) \text {Subst}\left (\int \frac {1}{2 c-x^2} \, dx,x,\sqrt {c-i c \tan (e+f x)}\right )}{a f} \\ & = -\frac {3 i \sqrt {2} c^{5/2} \text {arctanh}\left (\frac {\sqrt {c-i c \tan (e+f x)}}{\sqrt {2} \sqrt {c}}\right )}{a f}+\frac {3 i c^2 \sqrt {c-i c \tan (e+f x)}}{a f}+\frac {i c^2 (c-i c \tan (e+f x))^{3/2}}{a f (c+i c \tan (e+f x))} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
Time = 1.15 (sec) , antiderivative size = 53, normalized size of antiderivative = 0.42 \[ \int \frac {(c-i c \tan (e+f x))^{5/2}}{a+i a \tan (e+f x)} \, dx=\frac {i \operatorname {Hypergeometric2F1}\left (2,\frac {5}{2},\frac {7}{2},-\frac {1}{2} i (i+\tan (e+f x))\right ) (c-i c \tan (e+f x))^{5/2}}{10 a f} \]
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Time = 0.58 (sec) , antiderivative size = 95, normalized size of antiderivative = 0.76
method | result | size |
derivativedivides | \(\frac {2 i c^{2} \left (\sqrt {c -i c \tan \left (f x +e \right )}-4 c \left (-\frac {\sqrt {c -i c \tan \left (f x +e \right )}}{8 \left (\frac {c}{2}+\frac {i c \tan \left (f x +e \right )}{2}\right )}+\frac {3 \sqrt {2}\, \operatorname {arctanh}\left (\frac {\sqrt {c -i c \tan \left (f x +e \right )}\, \sqrt {2}}{2 \sqrt {c}}\right )}{8 \sqrt {c}}\right )\right )}{f a}\) | \(95\) |
default | \(\frac {2 i c^{2} \left (\sqrt {c -i c \tan \left (f x +e \right )}-4 c \left (-\frac {\sqrt {c -i c \tan \left (f x +e \right )}}{8 \left (\frac {c}{2}+\frac {i c \tan \left (f x +e \right )}{2}\right )}+\frac {3 \sqrt {2}\, \operatorname {arctanh}\left (\frac {\sqrt {c -i c \tan \left (f x +e \right )}\, \sqrt {2}}{2 \sqrt {c}}\right )}{8 \sqrt {c}}\right )\right )}{f a}\) | \(95\) |
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 261 vs. \(2 (98) = 196\).
Time = 0.25 (sec) , antiderivative size = 261, normalized size of antiderivative = 2.09 \[ \int \frac {(c-i c \tan (e+f x))^{5/2}}{a+i a \tan (e+f x)} \, dx=-\frac {{\left (3 \, \sqrt {2} a \sqrt {-\frac {c^{5}}{a^{2} f^{2}}} f e^{\left (2 i \, f x + 2 i \, e\right )} \log \left (-\frac {12 \, {\left (i \, c^{3} + {\left (a f e^{\left (2 i \, f x + 2 i \, e\right )} + a f\right )} \sqrt {-\frac {c^{5}}{a^{2} f^{2}}} \sqrt {\frac {c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}}\right )} e^{\left (-i \, f x - i \, e\right )}}{a f}\right ) - 3 \, \sqrt {2} a \sqrt {-\frac {c^{5}}{a^{2} f^{2}}} f e^{\left (2 i \, f x + 2 i \, e\right )} \log \left (-\frac {12 \, {\left (i \, c^{3} - {\left (a f e^{\left (2 i \, f x + 2 i \, e\right )} + a f\right )} \sqrt {-\frac {c^{5}}{a^{2} f^{2}}} \sqrt {\frac {c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}}\right )} e^{\left (-i \, f x - i \, e\right )}}{a f}\right ) + 2 \, \sqrt {2} {\left (-3 i \, c^{2} e^{\left (2 i \, f x + 2 i \, e\right )} - i \, c^{2}\right )} \sqrt {\frac {c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}}\right )} e^{\left (-2 i \, f x - 2 i \, e\right )}}{2 \, a f} \]
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\[ \int \frac {(c-i c \tan (e+f x))^{5/2}}{a+i a \tan (e+f x)} \, dx=- \frac {i \left (\int \frac {c^{2} \sqrt {- i c \tan {\left (e + f x \right )} + c}}{\tan {\left (e + f x \right )} - i}\, dx + \int \left (- \frac {c^{2} \sqrt {- i c \tan {\left (e + f x \right )} + c} \tan ^{2}{\left (e + f x \right )}}{\tan {\left (e + f x \right )} - i}\right )\, dx + \int \left (- \frac {2 i c^{2} \sqrt {- i c \tan {\left (e + f x \right )} + c} \tan {\left (e + f x \right )}}{\tan {\left (e + f x \right )} - i}\right )\, dx\right )}{a} \]
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Time = 0.30 (sec) , antiderivative size = 128, normalized size of antiderivative = 1.02 \[ \int \frac {(c-i c \tan (e+f x))^{5/2}}{a+i a \tan (e+f x)} \, dx=\frac {i \, {\left (\frac {3 \, \sqrt {2} c^{\frac {7}{2}} \log \left (-\frac {\sqrt {2} \sqrt {c} - \sqrt {-i \, c \tan \left (f x + e\right ) + c}}{\sqrt {2} \sqrt {c} + \sqrt {-i \, c \tan \left (f x + e\right ) + c}}\right )}{a} - \frac {4 \, \sqrt {-i \, c \tan \left (f x + e\right ) + c} c^{4}}{{\left (-i \, c \tan \left (f x + e\right ) + c\right )} a - 2 \, a c} + \frac {4 \, \sqrt {-i \, c \tan \left (f x + e\right ) + c} c^{3}}{a}\right )}}{2 \, c f} \]
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\[ \int \frac {(c-i c \tan (e+f x))^{5/2}}{a+i a \tan (e+f x)} \, dx=\int { \frac {{\left (-i \, c \tan \left (f x + e\right ) + c\right )}^{\frac {5}{2}}}{i \, a \tan \left (f x + e\right ) + a} \,d x } \]
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Time = 0.38 (sec) , antiderivative size = 109, normalized size of antiderivative = 0.87 \[ \int \frac {(c-i c \tan (e+f x))^{5/2}}{a+i a \tan (e+f x)} \, dx=\frac {c^2\,\sqrt {c-c\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}}\,2{}\mathrm {i}}{a\,f}-\frac {\sqrt {2}\,{\left (-c\right )}^{5/2}\,\mathrm {atan}\left (\frac {\sqrt {2}\,\sqrt {c-c\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}}}{2\,\sqrt {-c}}\right )\,3{}\mathrm {i}}{a\,f}+\frac {c^3\,\sqrt {c-c\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}}\,2{}\mathrm {i}}{a\,f\,\left (c+c\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}\right )} \]
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